What is the total impedance of a parallel circuit with two 8 ohm loudspeakers and two 16 ohm loudspeakers?

What is the total impedance of a parallel circuit with two 8 ohm loudspeakers and two 16 ohm loudspeakers?

• A. 3.2 ohms
• B. 4.0 ohms
• C. 2.7 ohms
• D. 5.0 ohms

Answer: (C)

To determine the total impedance of a parallel circuit with multiple resistive loads, one would use the formula for total impedance in parallel circuits. For loudspeakers in parallel, the correct approach involves calculating the reciprocal of the sum of the reciprocals of each load's impedance. In this instance, you have two 8-ohm loudspeakers and two 16-ohm loudspeakers. The calculation can be broken down as follows: 1. Convert each impedance to its reciprocal. - For the two 8-ohm speakers: \[ \frac{1}{8} + \frac{1}{8} = \frac{2}{8} = \frac{1}{4} \] - For the two 16-ohm speakers: \[ \frac{1}{16} + \frac{1}{16} = \frac{2}{16} = \frac{1}{8} \] 2. Now add the two results together: \[ \frac{1}{4} + \frac{1}{8} \] To add these, find a common denominator (which is 8): \[ \frac{2}{

To determine the total impedance of a parallel circuit with multiple resistive loads, one would use the formula for total impedance in parallel circuits. For loudspeakers in parallel, the correct approach involves calculating the reciprocal of the sum of the reciprocals of each load's impedance.

In this instance, you have two 8-ohm loudspeakers and two 16-ohm loudspeakers. The calculation can be broken down as follows:

1. Convert each impedance to its reciprocal.

• For the two 8-ohm speakers:

[

\frac{1}{8} + \frac{1}{8} = \frac{2}{8} = \frac{1}{4}

]

• For the two 16-ohm speakers:

[

\frac{1}{16} + \frac{1}{16} = \frac{2}{16} = \frac{1}{8}

]

2. Now add the two results together:

[

\frac{1}{4} + \frac{1}{8}

]

To add these, find a common denominator (which is 8):

[

\frac{2}{